x^2 - 5x - 4 ≤ 10 subtract 10 from both sides
x^2 - 5x - 14 ≤ 0 set this = 0 and factor
(x - 7)(x +2) = 0 so x = 7 and x = -2
So we have three iintervals here to evaluate x ≤ -2, -2 ≤ x ≤ 7 and x ≥ 7
So using (x-7)(x+2) and testing x =-3 makes this > 0
And testing x = 0 makes (x-7)(x +2) < 0
And testing x = 8 makes it > 0
So our answer is
-2 ≤ x ≤ 7