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How many solutions does the equation have?Let\[f(x)={x+3if x0,2x5if x>0.\]

 Oct 28, 2023
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Ifx≤0, then [f(f(x)) = f(-x + 3) = 2(-x + 3) - 5 = -2x + 1.]If x>0, then [f(f(x)) = f(2x - 5) = -2x - 5 + 3 = -2x - 2.]Hence,our problem is reduced to the two equations 2x+1=4 2x2=4.The first equation is solved byx=23​,and the second equation is solved byx=−3.Since each solution satisfies the corresponding inequality,there are2​solutions.

 Oct 28, 2023

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