Point \(X\) is on \(\overline{AC}\) such that \(AX = 4\cdot CX = 12\) . We know \(\angle ABC = \angle BXA = 90^\circ.\) What is \(BX\)?
AX = 12
AX = 4 CX
So....CX = 3
And we have this relationship
AX/ BX = BX / CX
AX * CX = BX^2
12 * 3 = BX^2
36 = BX^2 take both roots
6 = BX
