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Point \(X\) is on \(\overline{AC}\) such that \(AX = 4\cdot CX = 12\)  . We know \(\angle ABC = \angle BXA = 90^\circ.\) What is \(BX\)?

 

 

 

 Nov 1, 2019
 #1
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AX  = 12

AX  =  4 CX  

So....CX  = 3

 

And we have this relationship

 

AX/ BX  = BX / CX

 

AX * CX  =  BX^2

 

12 * 3  =  BX^2

 

36   =  BX^2        take both roots

 

6  =   BX

 

 

cool cool cool

 Nov 1, 2019

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