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Given f(x)=1/3(4-x)^2 , what is the value of f(16)?

 Apr 9, 2019
 #1
avatar+105238 
+2

I think this is    (1/3) (4 - x)^2  

 

So

 

f(16)  =   (1/3)(4 - 16)^2   =  (1/3)(-12)^2  = (1/3)(144)  =  48

 

 

cool cool cool

 Apr 9, 2019
 #2
avatar+1096 
+2

\(f(x)=\frac{1}{3(4-x)^2}\)

\(\frac{1}{3(4-16)^2}=\frac{1}{3\times 144}=\frac{1}{432}\)

 

You are very welcome!

:P

 Apr 9, 2019

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