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Given f(x)=1/3(4-x)^2 , what is the value of f(16)?

Guest Apr 9, 2019

CPhill · Answer 1 · 2019-04-09T02:37:13

I think this is (1/3) (4 - x)^2

So

f(16) = (1/3)(4 - 16)^2 = (1/3)(-12)^2 = (1/3)(144) = 48

CoolStuffYT · Answer 2 · 2019-04-09T06:06:17

$f(x)=\frac{1}{3(4-x)^2}$

$\frac{1}{3(4-16)^2}=\frac{1}{3\times 144}=\frac{1}{432}$

You are very welcome!

:P