The equation y = -16t^2 + 60t describes the height (in feet) of a projectile launched from the ground at 60 feet per second upward. In how many seconds will the projectile first reach 56 feet in height? Express your answer as a decimal rounded to the nearest hundredth.

xXxTenTacion Jul 8, 2018

#1**-1 **

Solve for t:

56 = 60 t - 16 t^2

56 = 60 t - 16 t^2 is equivalent to 60 t - 16 t^2 = 56:

60 t - 16 t^2 = 56

Divide both sides by -16:

t^2 - (15 t)/4 = -7/2

Add 225/64 to both sides:

t^2 - (15 t)/4 + 225/64 = 1/64

Write the left hand side as a square:

(t - 15/8)^2 = 1/64

Take the square root of both sides:

t - 15/8 = 1/8 or t - 15/8 = -1/8

Add 15/8 to both sides:

t = 2 or t - 15/8 = -1/8

Add 15/8 to both sides:

t = 7/4 = 1.75 seconds. But after 1.75 seconds it continues to go up for about 1/4 foot. And coming down to 56 feet again at exactly t= 2 seconds.

Note: somebody should check this.

Guest Jul 8, 2018