A company is deciding whether to package a ball in a cubic in a cubic box or a cylinder box. In either case, the ball will touch the bottom, top, and sides. What portion of the space inside the cylindrical box is empty?
This site calculator will solve symbolic math. You can use it to test your solutions.
This returns the solution for the question above.
solve→c1,d,c2,c3(c1=π×d36c2=π×d34c3=(1−(c1c2)))⇒{c1=0d=0c2=0c3=r12c1=r133×π6d=r13c2=r133×π4c3=13}
The result is the same as CPhill’s solution.
Note that all the Cs & Ds are not affecting the result. This calculator has a high resistance to CDD
Here’s another one
solve→c1,d,c2,x(c1=2×π×0.5dc2=2×π×(0.5d+x)c2=c1+1)⇒{c1=r9×πd=r9c2=r9×π+1x=1(2×π)}
^ - - - Does anyone know what it is for? It’s easy.
This one is totally symbolic.
solve→c2(c2×d2t2=c1×d1t1)⇒c2=c1×d1×t2(d2×t1)
The volume of the cylinder is
V = pi * r^2 * h where r is the radius of the cylinder and h is the height.
And the radius of the ball = the radius of the cylinder.
But since the ball touches the sides, top and bottom, the height of the cylinder must be 2r.
So the volume of the cylinder is
V = pi * r^2 * 2r = 2pi *r^3
And the volume of the ball is
V = (4/3)pi* r^3
So..... the portion of the cylinder that is filled by the ball (in terms of a ratio) is
[(4/3)pi * r^3] / [ 2 pi * r^3] = (4/3)/2 = 4/6 = 2/3 of the cylinder
So....the empty portion, in terms of ratio = 1/3 of the cylinder
This site calculator will solve symbolic math. You can use it to test your solutions.
This returns the solution for the question above.
solve→c1,d,c2,c3(c1=π×d36c2=π×d34c3=(1−(c1c2)))⇒{c1=0d=0c2=0c3=r12c1=r133×π6d=r13c2=r133×π4c3=13}
The result is the same as CPhill’s solution.
Note that all the Cs & Ds are not affecting the result. This calculator has a high resistance to CDD
Here’s another one
solve→c1,d,c2,x(c1=2×π×0.5dc2=2×π×(0.5d+x)c2=c1+1)⇒{c1=r9×πd=r9c2=r9×π+1x=1(2×π)}
^ - - - Does anyone know what it is for? It’s easy.
This one is totally symbolic.
solve→c2(c2×d2t2=c1×d1t1)⇒c2=c1×d1×t2(d2×t1)