Let ABCD be a trapezoid with bases AB and CD. Let AD=5 and BC=7, and let P be a point on side CD such that CP/DP=7/5. Let X,Y be the feet of the altitudes from P to AD, BC respectively. Show that PX=PY.
+1486 Let ABCD be a trapezoid with bases AB and CD. Let AD=5 and BC=7, and let P be a point on side CD such that CP/DP=7/5. Let X and Y be the feet of the altitudes from P to AD, BC respectively. Show that PX=PY.
DC = 12 | DP = 5 | CP = 7 | DM = CN = 4.5 | AD = 5 | BC = 7
∠ADM = ∠DPX ∠BCN = ∠CPY ( See diagram )
PX = cos(∠DPX) * DP = 4.5
PY = cos(∠CPY) * CP = 4.5
DM = CN = PX = PY 
