Questions and Answers I'm not sure about on Math Test Pt. 2

So for (1) and (2) you 1st need to find the gradient using the formular
m = (y2 - y1) / (x2 - x1) or if you prefer m = (y1 - y2) / (x1 -x2) [both formulars give same result]
Then once you get that substitute it into the formular y - y1 = m(x - x1)

(1) m = (2 - -1) / (-4 - 1)
= -(3/5)
therefore y - -1 = -(3/5) (x - 1)
y + 1 = -(3/5)x + (3/5)
y = -(3/5)x + (3/5) - 1
= - (3/5)x +3/5 - 5/5
= -(3/5)x - 2/5

(2) m = (5 - -1) / (3 - -2)
= 6/5
therefore y - - 1 = 6/5(x - - 2)
y + 1 = 6/5(x + 2)
y = (6/5)x + 12/5 - 1
= (6/5)x + 12/5 - 5/5
= (6/5)x + 7/5

For (3) you need to be aware that gradient of a line that is perpindicular to another line = -(1/m).
So the gradient of a line that is perpendicular to (Y = 2X + 3) = -(1/2).
Substituting that into the formular y - y1 = m(x - x1) gives you
y - 4 = -(1/2)(x - 3)
y = -(1/2)x + 3/2 +4
= -(1/2)x +3/2 + 8/2
= -(1/2)x + 11/2

Thank you so much for your help! I really appreciate it.