1. ∫ 3x dx = 3x/ ln 3 + constant , (C)
So
4 = 3x / ln 3 + C
4 = 31 / ln 3 + C
4 - 3 / ln 3 = C ≈ 1.27
So
3x/ln 3 + 1.27
2.
∫ 3 / sqrt ( 1 - x^2) dx = 3arcsin x + C
2 = 3 arcsin (0) + C (arcsin 0 = 0 )
(0, 2)
2 = 0 + C
2 = C
So
3arcsin x + 2
looks like i got the first one correct! Which is awesome!
The second one however, I see where i made my mistake, very simple one that i should have caught! I will take note.
Thank you CPhill!