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in the equation y = x^2-4x+5, the discriminate is positive (?) therefore there are two answers, yet my textbook says the discriminate is negative ??? help!

Guest Jul 29, 2017

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 #1
avatar+89763 
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It is discriminant  Not discrimante   :)

 

\(y = x^2-4x+5\\ \triangle=b^2-4ac\\ \triangle=(-4)^2-4*1*5=16-20=-4<0\\\)

 

The discriminant is -4 which is negative so there are no real roots :)

Melody  Jul 29, 2017
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1+0 Answers

 #1
avatar+89763 
+3
Best Answer

It is discriminant  Not discrimante   :)

 

\(y = x^2-4x+5\\ \triangle=b^2-4ac\\ \triangle=(-4)^2-4*1*5=16-20=-4<0\\\)

 

The discriminant is -4 which is negative so there are no real roots :)

Melody  Jul 29, 2017

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