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(2x2)-4

Guest Jan 9, 2018
edited by Guest  Jan 9, 2018

Best Answer 

 #1
avatar+2257 
+2

Let's use the exponent rules to simplify this expression.

 

\(\left(2x^2\right)^{-4}=2^{-4}\left(x^2\right)^{-4}\) by the power of a product exponent rule.

\(2^{-4}\left(x^2\right)^{-4}=2^{-4}x^{-8}\)   by the power of a power exponent rule.

\(2^{-4}x^{-8}=\frac{1}{2^4x^8}\)               by the negative power exponent rule.

\(\frac{1}{2^4x^8}=\frac{1}{16x^8}\)                     This step does not involve an exponent rule but rather this is just simplification.

TheXSquaredFactor  Jan 9, 2018
 #1
avatar+2257 
+2
Best Answer

Let's use the exponent rules to simplify this expression.

 

\(\left(2x^2\right)^{-4}=2^{-4}\left(x^2\right)^{-4}\) by the power of a product exponent rule.

\(2^{-4}\left(x^2\right)^{-4}=2^{-4}x^{-8}\)   by the power of a power exponent rule.

\(2^{-4}x^{-8}=\frac{1}{2^4x^8}\)               by the negative power exponent rule.

\(\frac{1}{2^4x^8}=\frac{1}{16x^8}\)                     This step does not involve an exponent rule but rather this is just simplification.

TheXSquaredFactor  Jan 9, 2018

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