The height (in meters) of a shot cannonball follows a trajectory given by \(h(t) = -4.9t^2 + 14t - 0.4\) at time \(t\) (in seconds). As an improper fraction, for how long is the cannonball above a height of \(6\) meters?
12/7 sec
Yes! 16/7-4/7=12/7. Thank you!
Nice work, MathToo !
