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The height (in meters) of a shot cannonball follows a trajectory given by \(h(t) = -4.9t^2 + 14t - 0.4\) at time \(t\) (in seconds). As an improper fraction, for how long is the cannonball above a height of \(6\) meters?

 Dec 29, 2018
 #1
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0

12/7  sec

 Dec 29, 2018
 #2
avatar+816 
+1

Yes! 16/7-4/7=12/7. Thank you!

mathtoo  Dec 29, 2018
 #3
avatar+23593 
0

Nice work, MathToo !

ElectricPavlov  Dec 29, 2018

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