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Triangle \(ABC\) has a right angle at \(B\). Legs \(\overline{AB}\) and \(\overline{CB}\) are extended past point \(B \) to points \(D\) and \(E\), respectively, such that \(\angle EAC = \angle ACD = 90^\circ\). Prove that \(EB \cdot BD = AB \cdot BC\).

Draw a picture!

 Jul 23, 2019
 #1
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Here :  https://web2.0calc.com/questions/help-please_10141

 

cool cool cool

 Jul 23, 2019

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