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Quick questions simple but not completely sure how to do it.

Guest Oct 31, 2017

Best Answer 

 #1
avatar+17655 
+2

a)  Numerator:         (x2y)2·(xy)3·z2  = (x2y)·(x2y)·(xy)·(xy)·(xy)·z2  =  [x2·x2·x·x·x]·[y·y·y·y·y]·z2  =  x7·y5·z2

     Denominator:     (xy2)2·y·z  =  (xy2)·(xy2)·y·z  =  [x·x]·[y2·y2·y]·z  =  x2·y5·z

 

    Combining the numerator and denominator:     [x7·y5·z2] / [x2·y5·z]  =  x5·z

 

b)  Numerator:  (12)2·(63)·52  =  (2·2·3)2·(23·32)·52  =  (22·3)2·(23·32)·52​  = 24·33·23·32·52  =  27·35·52

     Denominator:     (2·3·3)2·(3·5)  =  (2·32)2·(3·5)  =  22·34·3·5  =  22·35·5

 

     Combining the numerator and denominator:  [27·35·52] / [22·35·5]  =  25·5  =  160

 

You'll need to answer part c.

geno3141  Oct 31, 2017
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1+0 Answers

 #1
avatar+17655 
+2
Best Answer

a)  Numerator:         (x2y)2·(xy)3·z2  = (x2y)·(x2y)·(xy)·(xy)·(xy)·z2  =  [x2·x2·x·x·x]·[y·y·y·y·y]·z2  =  x7·y5·z2

     Denominator:     (xy2)2·y·z  =  (xy2)·(xy2)·y·z  =  [x·x]·[y2·y2·y]·z  =  x2·y5·z

 

    Combining the numerator and denominator:     [x7·y5·z2] / [x2·y5·z]  =  x5·z

 

b)  Numerator:  (12)2·(63)·52  =  (2·2·3)2·(23·32)·52  =  (22·3)2·(23·32)·52​  = 24·33·23·32·52  =  27·35·52

     Denominator:     (2·3·3)2·(3·5)  =  (2·32)2·(3·5)  =  22·34·3·5  =  22·35·5

 

     Combining the numerator and denominator:  [27·35·52] / [22·35·5]  =  25·5  =  160

 

You'll need to answer part c.

geno3141  Oct 31, 2017

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