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cos^2(X)=.79??

 Nov 20, 2016
 #1
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it´s not possible that cos^2(X)>1...

 Nov 20, 2016
 #2
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That is incorrect.

 

\(-1\le cos^2(X)\le1\\~\\ cos^2(X)=.79\\ cos(X)=\pm\sqrt{0.79}\)

 

 

acos(sqrt(0.79)) = 27.274728680412

 

\(X\approx 180n\pm 27.3^\circ \qquad n\in Z\)

Melody  Nov 20, 2016
 #3
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cos^2(x)=.79 (=0.79) for x=0.48

 

edit: (0.48 rad x 180 deg) / Pi rad= 27.501974166279514 deg

 Nov 20, 2016
edited by Guest  Nov 20, 2016

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