((r^n)^2)/(r^(6-2n))

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Guest Feb 24, 2015

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Best Answer

$$\\\frac{(r^n)^2}{r^{6-2n}}\\\\
=\frac{(r^{2n})}{r^{6-2n}}\\\\
=r^{2n-(6-2n)}\\\\
=r^{2n-6+2n)}\\\\
=r^{4n-6}\\\\$$

Melody Feb 24, 2015

Melody · Answer 1 · 2015-02-24T12:24:49

$$\\\frac{(r^n)^2}{r^{6-2n}}\\\\
=\frac{(r^{2n})}{r^{6-2n}}\\\\
=r^{2n-(6-2n)}\\\\
=r^{2n-6+2n)}\\\\
=r^{4n-6}\\\\$$

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Badinage · Answer 2 · 2015-02-24T12:16:45

$${\frac{{{\mathtt{r}}}^{{\mathtt{2}}{n}}}{{{\mathtt{r}}}^{\left({\mathtt{6}}{\mathtt{\,-\,}}{\mathtt{2}}{n}\right)}}}$$

$${\frac{{{\mathtt{r}}}^{{\mathtt{4}}{n}}}{{{\mathtt{r}}}^{{\mathtt{6}}}}}$$

= $${{\mathtt{r}}}^{\left({\mathtt{4}}{n}{\mathtt{\,-\,}}{\mathtt{6}}\right)}$$

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Melody · Answer 3 · 2015-02-24T12:25:35

sorry Badinage - your answer was not up yet when I started.