+379 Let's solve your equation step-by-step.
x−6=√3x
Step 1: Flip the equation.
√3x=x−6
Step 2: Solve Square Root.
√3x=x−6
3x=(x−6)2(Square both sides)
3x=x2−12x+36
3x−(x2−12x+36)=x2−12x+36−(x2−12x+36)(Subtract x^2-12x+36 from both sides)
−x2+15x−36=0
(−x+3)(x−12)=0(Factor left side of equation)
−x+3=0 or x−12=0(Set factors equal to 0)
x=3 or x=12
Check answers. (Plug them in to make sure they work.)
x=3(Doesn't work in original equation)
x=12(Works in original equation)
+37157 Square both sides to get
x^2 -12x+36 = 3x simplify
(x^2 - 15x + 36) = 0 factor
(x-12)(x-3) = 0 so x = 12 or 3
sub into original equation to find if they work 12 does 3 is extraneous
