+50 radical 32- 7 radical 2 pls help i dont know how to do this
+9479 First, simplify the square root of 32.
\(\sqrt{32}-7\sqrt2\\~\\ =\sqrt{2\cdot2\cdot2\cdot2\cdot2}-7\sqrt2 \\~\\ =\sqrt{2\cdot2}\cdot\sqrt{2\cdot2}\cdot\sqrt2-7\sqrt2 \\~\\ =2\cdot2\cdot\sqrt2-7\sqrt2 \\~\\ =4\sqrt2-7\sqrt2\)
4 cookies - 7 cookies = -3 cookies.
\(4\sqrt2-7\sqrt2=-3\sqrt2\)
So..the most simplified form is: \(-3\sqrt2\) 
+9479 First, simplify the square root of 32.
\(\sqrt{32}-7\sqrt2\\~\\ =\sqrt{2\cdot2\cdot2\cdot2\cdot2}-7\sqrt2 \\~\\ =\sqrt{2\cdot2}\cdot\sqrt{2\cdot2}\cdot\sqrt2-7\sqrt2 \\~\\ =2\cdot2\cdot\sqrt2-7\sqrt2 \\~\\ =4\sqrt2-7\sqrt2\)
4 cookies - 7 cookies = -3 cookies.
\(4\sqrt2-7\sqrt2=-3\sqrt2\)
So..the most simplified form is: \(-3\sqrt2\)
+9479 I did it using the LaTeX button right next to the image button...
Erase the stuff that is already inside and then click the " Math " button in the top left. At the bottom of the list there is a little picture of a square root. You can just click that and then type the number that you want to go underneath between the {} s.
Also..you can copy and pase this: √[ ]
And just type what goes under between the parenthesees :)
Or.....you can just type sqrt( ) 
