radicals

claire24:

how do you solve the equation: square root of (2x+8)-2 times the square root of x = 0

sqrt(2x+8)-2sqrt(x) = 0

sqrt(2x+8) = 2sqrt(x)

sqrt(2x+8) = sqrt(4)sqrt(x)

sqrt(2x+8) = sqrt(4x)

2x+8=4x

8 = 2x
x=4