whats the radius and diameter if the area= 706.5
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\(\pi r^2=A\ |\ :\pi \\ r^2= \dfrac{A}{\pi }\ |\ \sqrt{}\\ r=\sqrt{\frac{A}{\pi}}=\sqrt{\frac{706.5}{\pi}}\\\)
\(r=15\)
\(d=2r \)
\(d=30\)
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