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At 2:00 p.m. two cars start toward each other from towns 240 miles apart. If the rate of one car is 10 mph faster than the other, how fast does each car go if they meet at 5:00 p.m? and  If 3x represents the distance that the slower car traveled, then which expression represents the distance the faster car traveled?

 

A) 3(240)

B) 3x + 10

C) 3x + 30

 Jun 12, 2019
 #1
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They travel for 3 hours.....and the total distance covered = 240 miles

 

Let x be the rate of the slower car    and x + 10  be the rate of the faster

 

And    R*T  = D    so

 

3(x) + 3(x + 10) = 240

 

3x +  (3x + 30)  = 240

 

 

cool cool cool

 Jun 12, 2019
 #2
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Absolutely genius!

I have decided this task by system of two equations and series of expressions:-) You have short and smart solution!

Guest Jun 13, 2019

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