+466 The first time Henry made the trip he drove at 10mph and got there 5 hours late. The next time he drove at 25 mph and got there 1 hour early. How long was the trip?
+5265 I'm guessing you mean in miles, so let's find out.
So, the first time, he drove 10mph and got there 5 hrs late. Then he drove 15mph faster and got there 1hr early. So this corresponds to 5mph=2hrs, or 2.5mph. The trip there, if it lasts an hour, should be 22.5 miles.
+466 That answer doesn't fully cover it, but thanks for trying. The trip cannot be 22.5 miles, because if you were driving 10mph it would never take you 5 hours too long. Thanks for trying though. 
x=the distance t= time
x/10 = t + 5
x/25 = t - 1
x/10 - x/25 = (t+5) - (t-1)
5x/50 - 2x/50 = 6
3x/50 = 6
3x=300
x=100 miles
+129847 Here's another way to do this......let the normal driving time = T
And Rate * Time = D .....so....since the distances equate......
10(T + 5) = 25(T - 1) (1)
10T + 50 = 25T - 25
75 = 15T divide both sides by 15
T = 5
So......using either side of (1), the distance is 10(5 + 5) = 10 * 10 = 100 miles
