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When Edith finishes the race, how far behind is Foley, in km?

Hello Lilliam0216!

$v_d=24km/t_d\\ v_e=(24-5)km/t_d=19km/t_d\\ v_f=(24-6)km/t_d=18km/t_d\\ t_e=\frac{24km}{v_e}=\frac{24km\cdot t_d}{19km}\\ s_f=v_f\cdot t_e=\frac{18km}{t_d}\cdot \frac{24km\cdot t_d}{19km}=22.737km$

Foley was (24-22.737)km=1.263km behind when Edith finished the race.

  !