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[size=150]If (sin 65 + cos 67)(sin 40 - cos 33) = (sin 65 - cos 67)(sin 40 + cos 33), prove that sin 65 / cos 67 = sin 40 / cos 33 (without considering actual value)[/size]
 Jun 1, 2012
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this equation becomes very easy one, if you just write it like this:
(a+b)(c-d)=(a-b)(c+d), and need to prove a/b=c/d
here a=sin65
b=cos67
c=sin40
d=cos33
from (a+b)(c-d)=(a-b)(c+d) we'll get
ac-ad+bc-bd=ac+ad-bc-bd
bc-ad=ad-bc
2bc=2ad
bc=ad
ad=bc
a/b=c/d
 Jun 2, 2012

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