I am working on a worksheet for math and im stuck on this problem. its a rational equation and I know the answer but he told us to show our work. The answers are 1 and 7/2.

the problem is 4=(5m-5)/(7m)-(6m^2-50m+16)/(7m)

Can anyone help me out? please email me at chancehammond@bellsouth.net

thanks, chance

the problem is 4=(5m-5)/(7m)-(6m^2-50m+16)/(7m)

Can anyone help me out? please email me at chancehammond@bellsouth.net

thanks, chance

Guest Feb 19, 2012

#1**0 **

[input]4=(5x-5)/(7x)-(6x^2-50x+16)/(7x)[/input]

4=((5x-5)-(6x^2-50x+16))/(7x)

4=(5x-5-6x^2+50x-16)/(7x)

4=(-6x^2+55x-21)/(7x)

28x=-6x^2+55x-21

28x-55x= -6x^2-21

-27x = -6x^2-21

-6x^2+27x-21=0

-6*(x^2-27x/6+21/6)=0

-6*(x^2-27x/6+21/6) is zero, if (x^2-27x/6+21/6) is zero:

x_{1,2} = -p/2 +- sqrt( (p/2)^2 - q )

p = -27/6

q = 21/6

x1 = -(-27/6)/2 + sqrt( ((-27/6)/2)^2 - 21/6 )

[input]-(-27/6)/2 + sqrt( ((-27/6)/2)^2 - 21/6 )[/input]

**x1 = 3.5 = 7/2**

x2 = -(-27/6)/2 - sqrt( ((-27/6)/2)^2 - 21/6 )

[input]-(-27/6)/2 - sqrt( ((-27/6)/2)^2 - 21/6 )[/input]

**x2 = 1**

4=((5x-5)-(6x^2-50x+16))/(7x)

4=(5x-5-6x^2+50x-16)/(7x)

4=(-6x^2+55x-21)/(7x)

28x=-6x^2+55x-21

28x-55x= -6x^2-21

-27x = -6x^2-21

-6x^2+27x-21=0

-6*(x^2-27x/6+21/6)=0

-6*(x^2-27x/6+21/6) is zero, if (x^2-27x/6+21/6) is zero:

x

p = -27/6

q = 21/6

x1 = -(-27/6)/2 + sqrt( ((-27/6)/2)^2 - 21/6 )

[input]-(-27/6)/2 + sqrt( ((-27/6)/2)^2 - 21/6 )[/input]

x2 = -(-27/6)/2 - sqrt( ((-27/6)/2)^2 - 21/6 )

[input]-(-27/6)/2 - sqrt( ((-27/6)/2)^2 - 21/6 )[/input]

admin
Feb 19, 2012