$${{\left({{\mathtt{128}}}^{{\mathtt{3}}}\right)}}^{{\mathtt{x}}} = {\mathtt{8}}$$ pls explain how to solve, original problem does not have parentheses, original problem should be 128^3x=8
First take the log of both sides to bring out the 3x, divide both sides by log(128) then by 3.
log(128^(3x)) = log (8)3xlog(128) = log(8)3x = log(8) / log(128)x = (log(8) / log(128)) / 3x = 1/7
