I think this is what the problem is:
\(\frac{(4x^{4})^{\frac{1}{2}}y^{5}}{8x-3\sqrt{y^{12}}}\)
Well the square root of x is the same as saying x raised to the one half power.
The square root of 4x4 is 2x2
the square root of y12 is y6
\(\frac{(2x^{2})y^{5}}{8x-3(y^{6})}\)
y5 divided by y6 is 1/y
Now I think this is the simplest form:
\(\frac{2x^{2}}{8x-3y}\)
