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The integers G and H are chosen such that

\[\frac{G}{x+5}+\frac{H}{x^2-4x}=\frac{x^2-2x+10}{x^3+x^2-20x}\]
for all real values of $x$ except -5, 0, and 4. Find $H/G$.

 Feb 15, 2021
 #1
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The value of H/G is 8.

 Feb 21, 2021

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