The integers G and H are chosen such that
\[\frac{G}{x+5}+\frac{H}{x^2-4x}=\frac{x^2-2x+10}{x^3+x^2-20x}\] for all real values of $x$ except -5, 0, and 4. Find $H/G$.
The value of H/G is 8.
+148 
