+206 The integers $G$ and $H$ are chosen such that
Gx+5+Hx2−4x=x2−2x+10x3+x2−20x
for all real values of except $-5$, $0$, and $4$. Find $H/G$.
+37165 cross multiply the left side
gx^2 -g 4x + hx + 5 h = x^2 -2x+10 so g = 1 h = 2 take it from here ! 
