This is a continued fraction of a rational number in the form of a/b: 3, 3, 3, 3, 3, 3, 3, 3, 2. Need some help in finding a/b. Any hint or help would be appreciated. Thank you.
+128408
3, 3, 3, 3, 3, 3, 3, 3, 2
We take this this in reverse order to find the continued fraction....it is actually not as hard as it seems...just a (rather tedious) iterative process
So....We work from right to left
Take the last 2, invert it ⇒ 1/2....add it to the next-to-the-last 3 = 3 + 1/2 = 7/2
Invert this = 2/7 and add it to the next 3 to the left = 3 + 2/7 = 23/7
Invert this = 7/23 and add it to the next 3 to the left = 3 + 7/23 = 76/23
Invert this and add it to the next 3 on the left = 23/76 + 3 = 251/76
Invert this and add it to the next 3 on the left = 76/251 + 3 = 829/251
Invert this and add it to the next 3 on the left = 251 / 829 + 3 = 2738 / 829
Invert this and add it to the next 3 on the left = 829 / 2738 + 3 = 9043/2738
Invert this and add it to the last 3 on the left = 2738/9043 + 3 = 29867 / 9043 = a / b
