Consider a rectangle with a width of 𝑡 2−9 / 3𝑡−2 cm and a length of 15𝑡−10/ 3𝑡−9 cm.
Write and simplify an expression for the area of the rectangle. State the NPV’s.
Calculate the area of the rectangle if 𝑡 = 1 cm.
Thank you:)
+36916 Area = w * l
so the area is :
(𝑡^2−9 / 3𝑡−2) * ( 15𝑡−10/ 3𝑡−9) cm^2. (I assumed you meant t2 and NOT t 2 )
(t+3)(t-3) * (15t-10)
(3t-2)(3)(t-3) note that the (t-3) in the numerator and denominator cancel (t cannot = 3 or 2/3 )
(t+3) * (15t-10)
(3)(3t-2)
15t^2 +35t-30 = area when t = 1 (15 + 35-30)/(3) = 20 / 3 cm^2
(3)(3t-2)
