Rational

If the area is (x-3)/(x-2) and the length is 9x-3x^2, then the width is (x-3/(x-2) divided by 9x-3x^2. 

$\frac{\frac{x-3}{x-2}}{9x-3x^2}=\frac{x-3}{\left(x-2\right)\left(9x-3x^2\right)}=\frac{x-3}{\left(x-2\right)\cdot \:3x\left(3-x\right)}=-\frac{1}{3x\left(x-2\right)}$

JP