Rationalize the denominator of \(\displaystyle \frac{1}{\sqrt[3]{3} - \sqrt[3]{2}}\). With your answer in the form \(\displaystyle \frac{\sqrt[3]{A} + \sqrt[3]{B} + \sqrt[3]{C}}{D}\), and the fraction in lowest terms, what is \(A+B+C+D\)?
Hint : Multiply top / bottom by [ 3^(2/3) + 2^(2/3) + 6^(1/3) ]