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Rationalize the denominator of \(\displaystyle \frac{1}{\sqrt[3]{3} - \sqrt[3]{2}}\). With your answer in the form \(\displaystyle \frac{\sqrt[3]{A} + \sqrt[3]{B} + \sqrt[3]{C}}{D}\), and the fraction in lowest terms, what is \(A+B+C+D\)?

 Jul 12, 2022
 #1
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Hint :  Multiply  top / bottom  by     [ 3^(2/3)  + 2^(2/3) + 6^(1/3)  ]

 

 

cool cool cool

 Jul 12, 2022

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