Hello and thank you, yesterday was the first time I've used web2.0calc (your site came up when I was using google calculator), I would like to expand on the problem and thank you for the answers so far, maths is not my strong point and I'm really very grateful.
I’ve reworked a formula that patinas certain metals and to date, I've formulated as the answer(s) below. (answered by melody)
However, I'm basing this on a total solution of 1750ml, now what I'm trying to do is trying to calculate how much I will need for coverage:
so, I know that if I prepare the kit as follows A=1000ml B= 500ml C=250ml (based on a basic recipe I’ve found on-line), I can use the formula below to easy create a 300ml solution, however, the solutions need to be prepared fresh each time.
|1000||500||250||1750||1750/300 = 5.8333|
|171ml||86ml||43ml||300ml||answered by melody|
So I need to calculate how much I need for a given volume, so that SAxH for example 2000mm x 4000mm x 0.5mm gives me a volume required: SA =8000mm Volume 4000ml, the chemicals are expensive and work best if they just sit on the surface not submerged, so my tests show that height is 0.5mm (on a flat surface with surface tension) this is fixed, my question is with the existing formula how would i calculate the amount required for variable amounts such as I needed 4000ml or 2000ml for example, it would give me the amounts of A, B and C respectively.
|1000 ml Water||500 ml Water||250 ml Water|
|17g Chemical X||22g Chemical Y||11g Chemical Z|
SA = (W=2000 mm variable x L=4000 mm variable) =8000 mm sq x H (0.5mm fixed) = Volume 4000 ml
Hope this makes sense :-)