+0  
 
0
942
2
avatar+122 

I need help in my practical math class.

https://prnt.sc/kzlz86

https://prnt.sc/kzlzh7

 

(Copy and paste links)

Thanks! 

 Sep 28, 2018
 #1
avatar+128079 
+4

First one....

 

(a)   The two points that should be used are ≈  (1,14)  and ≈  (7,7)....these don't lie directly on the line, but they are very close to the line

 

(b)  Slope =  [ 7 - 14 ] / [ 7 - 1 ] =   -7 / 6  ≈  - 1.166

 

(c)  Equation of the linear model  in point- slope form  is

 

(y - 7) = -1.166(x - 7)

 

(d)  Equation of the linear model in slope-intercept form :

 

y  = -1.166x + 8.162 + 7

 

y = -1.166x + 15.162 

 

 

 

cool cool cool

 Sep 29, 2018
 #2
avatar+128079 
+4

Second one

 

a)

 

Linear regression equation         Coefficient of determination  (r^2)

 

y = 2.16x + .391                         .903

 

Quadratic regression equation   Coefficient of determination

 

y = .096x^2 + .714x  + 3.803             .948

 

Exponential regression equation     Coefficient of determination

 

y = 4.63 (1.152)^x                               .951

 

 

b)  The exponetial regression equation fits the data best   [ highest r^2   and r value  ]

 

 

cool cool cool

 Sep 29, 2018

3 Online Users

avatar
avatar