I am having problems with this equasion: $$\left({\frac{\left({\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{1}}\right)}{{\mathtt{x}}}}\right){\mathtt{\,-\,}}{\mathtt{2}}$$ accroding to the answer is $${\mathtt{\,-\,}}\left({\frac{\left({\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right)}{{\mathtt{x}}}}\right)$$
can someone give me the steps as to how this happens, or is the equasion wrong.
$$((x-1)/x)-2 = ((x-1)/x)-2x/x$$
$$=((x-1-2x)/x) = ((-x-1)/x) = -((x+1)/x)$$
First I multiply 2 by (x/x) which is equal to 1
Then since the denominators are equal I'm allowed to substract 2x from the nominator of the fraction.
This then can be rewritten to $$-((x+1)/x)$$
Reinout