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I am having problems with this equasion:  $$\left({\frac{\left({\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{1}}\right)}{{\mathtt{x}}}}\right){\mathtt{\,-\,}}{\mathtt{2}}$$ accroding to the answer is $${\mathtt{\,-\,}}\left({\frac{\left({\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right)}{{\mathtt{x}}}}\right)$$

can someone give me the steps as to how this happens, or is the equasion wrong.

 Apr 14, 2014
 #1
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$$((x-1)/x)-2 = ((x-1)/x)-2x/x$$

$$=((x-1-2x)/x) = ((-x-1)/x) = -((x+1)/x)$$

First I multiply 2 by (x/x) which is equal to 1

Then since the denominators are equal I'm allowed to substract 2x from the nominator of the fraction.

 

This then can be rewritten to $$-((x+1)/x)$$

 

Reinout

 Apr 14, 2014

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