+0  
 
0
315
1
avatar

I choose a random integer n between 1 and 10 inclusive. What is the probability that for the n  I chose, there exist no real solutions to the equation x(x + 1) = n ? Express your answer as a common fraction.

 Dec 13, 2020
 #1
avatar
0

There are only 2 integers for n that give solution to the equation:

 

And that is when n = 2  and  n = 6

 

Therefore, the probability that your n has no solution is: 8 / 10 = 4 / 5

 Dec 13, 2020

2 Online Users