Find the equation of the asymptote of the graph of \(r = \cos 2 \theta \sec \theta.\)
I would be good if you give me the answer with the solution becuase ive tried this prob for a while but its just so confusing on the theta part.
The exact answer and the solution would be greatly appreciated!
The derivative of cos(2x)*sec(x) is sec(x) (cos(2x) tan(x) - 2*sin(2x)). This is 0 when x is a multiple of pi.
Checking the multiples of pi, we see that minimum of the function occurs at x = pi, the minimum value is -1.
So the asymptote is y = -1.