\(\frac{dP}{dt}=rP(1-\frac{P}{K})\)
Rearrange the differential equation into standard form.
I feel like I've attacked this every way possible but I can't seem to get into standard form.
Any help is greatly appreciated,
Thank you.
I don't know what you mean by 'standard form'.
Assuming that the p inside the bracket is the same as the P at the front, the equation can be written as
\(\displaystyle \frac{dP}{dt}=\frac{rP}{K}(K-P),\)
from which we have, (assuming that the r and K are constants),
\(\displaystyle \int\frac{dP}{P(K-P)}=\frac{r}{K}\int dt.\)
Now it's a partial fractions job on the first integral.
Tiggsy