\(\frac{dP}{dt}=rP(1-\frac{P}{K})\)

Rearrange the differential equation into standard form.

I feel like I've attacked this every way possible but I can't seem to get into standard form.

Any help is greatly appreciated,

Thank you.

vest4R
Mar 26, 2018

#2**+2 **

I don't know what you mean by 'standard form'.

Assuming that the p inside the bracket is the same as the P at the front, the equation can be written as

\(\displaystyle \frac{dP}{dt}=\frac{rP}{K}(K-P),\)

from which we have, (assuming that the r and K are constants),

\(\displaystyle \int\frac{dP}{P(K-P)}=\frac{r}{K}\int dt.\)

Now it's a partial fractions job on the first integral.

Tiggsy

Guest Mar 26, 2018