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[input]4.3*10^-3=10.2(sqrt(2y*(147.83-51.9[/input] Estimate the following of y correct to one significant figure without using a calculator.

I have tried several times to try and solve this. I ended up with 0.016 as an estimate using the following method.

1. Round off: 4.0*^-3=10(sqrt(2y*(150-50)
2. Put 4.3*^-3 into standard form: 0.0043

Working out
0.0040=10(sqrt(2y*(150-50)

0.0040=10(sqrt(2y*100)

0.040=(sqrt(2y*100)

0.0016=y*10

0.016=y

I am not sure if I am even doing it wrong, however the estimate is way off the actual which is,[input]1281993656793721/1383922538849855006250000[/input]. I have a feeling my answer is correct but due to the rounding, it has caused the estimate to be very different.
 Dec 22, 2013
 #1
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[quote="CPlusHris"][input]4.3*10^-3=10.2(sqrt(2y*(147.83-51.9[/input] Estimate the following of y correct to one significant figure without using a calculator.

I have tried several times to try and solve this. I ended up with 0.016 as an estimate using the following method.

1. Round off: 4.0* 10^-3=10(sqrt(2y*(150-50)
2. Put 4.3*^-3 into standard form: 0.0043

Working out
0.0040=10(sqrt(2y*(150-50)

0.0040=10(sqrt(2y*100)

0. 00040=(sqrt(2y*100)

0.00000016=2y*100

0.0000000008

8 * 10^(-10)

Just a couple of little errors can make a big difference!

The actual answer is 9 * 10^(-10) Correct to 1 significant figure.

So your answer (and mine) does not quite have the accuracy that you were asked for.
But I still think that it is a sensible estimate.
 Dec 22, 2013
 #2
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Oh, now I see where I went wrong, instead of dividing 0.0040 by 10, I multiplied it.
Thanks for the help, much appreciated.

This question had me stumped for at least half an hour.
 Dec 22, 2013
 #3
avatar+118653 
0
You are very welcome Chris (I assume your name is Chris?)
It can be very frustrating when you get stuck on a question. I know this.
 Dec 23, 2013

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