Rectangle $ABCD$ contains a point $X$ such that $AX = 3$, $BX = 3$, and $CX = 3$. Find $DX$.
I would assume that DX = 3.
If CX, AX, and BX all equal three, the point X will have to be the center of the rectangle, so DX = 3.
C D
.x
A B
+1427 
