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Points $A$ and $B$ are on side $\overline{YZ}$ of rectangle $WXYZ$ such that $\overline{WA}$ and $\overline{WB}$ trisect $\angle ZWX$. If $WX = 2$ and $XY = 3$, then what is the area of rectangle $WXYZ$?

 Jan 12, 2024

Best Answer 

 #1
avatar+288 
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Hmm... I see that we already have all we need to find the area, WX and XY. we just multiply 2 by 3 and get 6.

 

Answer: 6

 Jan 12, 2024
 #1
avatar+288 
+1
Best Answer

Hmm... I see that we already have all we need to find the area, WX and XY. we just multiply 2 by 3 and get 6.

 

Answer: 6

DS2011 Jan 12, 2024

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