Points $A$ and $B$ are on side $\overline{YZ}$ of rectangle $WXYZ$ such that $\overline{WA}$ and $\overline{WB}$ trisect $\angle ZWX$. If $WX = 2$ and $XY = 3$, then what is the area of rectangle $WXYZ$?
Hmm... I see that we already have all we need to find the area, WX and XY. we just multiply 2 by 3 and get 6.
Answer: 6
+1678 
