In a certain rectangle, its length is 10 more than its width. If the area of the rectangle is 264, then what are the dimensions of the rectangle?
Area = l x w and l = 10w
264 = 10w * w = 10w^2
w^2 = 26.4 (w = sqrt 26.4) (l = 10 sqrt26.4)
w = 5.138 l = 51.38
In a certain rectangle, its length is 10 more than its width. If the area of the rectangle is 264, then what are the dimensions of the rectangle?
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width => x length => x + 10
x (x + 10) = 264
x2 + 10x - 264 = 0
x = 12
width = 12 length = 22
12 * 22 = 264