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In a certain rectangle, its length is 10 more than its width.  If the area of the rectangle is 264, then what are the dimensions of the rectangle?

 Feb 19, 2021
 #1
avatar+31013 
+1

Area = l x w        and   l = 10w

264 = 10w * w = 10w^2

w^2 = 26.4               (w = sqrt 26.4)            (l = 10 sqrt26.4)

w = 5.138      l = 51.38       

 Feb 19, 2021
 #3
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0

   Ahhh....misread the question.....frown

Thanx, jugoslav !  

Guest Feb 19, 2021
 #2
avatar+1164 
+5

In a certain rectangle, its length is 10 more than its width.  If the area of the rectangle is 264, then what are the dimensions of the rectangle?

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

width =>  x         length =>  x + 10

 

x (x + 10) = 264

 

x2 + 10x - 264 = 0

 

x = 12

 

width = 12         length = 22     

 

12 * 22 = 264 wink

 Feb 19, 2021
edited by jugoslav  Feb 19, 2021

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