Sides AH and BC of regular octagon ABCDEFGH are extended to meet at point P. What is the degree measure of angle P?
\(\phantom{AH and CD}\)
Triangle APB will be isosceles with angles A and B being equal
The measure of either angle = 180 - [ (8 - 2) (180) / 8 ] = 180 - (3/4)180 = 180 - 135 = 45°
So angle P = 180 - 2(45) = 90°
