+0  
 
0
224
1
avatar

If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find [ƒ(2) - g(1)] 2 <-- is to the power of two do i solve for fx and gx first and then use the power or do i multiply the brackets inside to the power first?

Guest Aug 15, 2017
 #1
avatar+7385 
0

Relations and functions

If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find [ƒ(2) - g(1)] 2 <-- is to the power of two do i solve for fx and gx first and then use the power or do i multiply the brackets inside to the power first?

 

\([f(x)-g(x)]^2 \)

\(=[f(1)-g(2)]^2\)

\(=[(1^2+1)-(3\cdot2+1)]^2 \)

\(=[2-7]^2\)

\(=[-5]^2\)

\(=25\)

Do solve for fx and gx first and then use the power.

laugh  !

asinus  Aug 15, 2017

7 Online Users

avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.