repeating decimal

since 0.54545454... is just $\frac{6}{11}$

we then know that 0.00545454... is $\frac{6}{1100}$ and 0.43 is just $\frac{43}{100}$,

0.43545454... = $\frac{(43)(\frac{1100}{10})}{1100}+\frac{6}{1100} = \frac{473 + 6}{1100} = \frac{479}{1100}$