Let . When is written out as a repeating decimal, what is the sum of the digits in a single repeating period? (In other words, what is the sum of the digits covered by the repeat bar?)
Let \(y=(0.\overline{12})+(0.\overline{345})\).
When y is written out as a repeating decimal, what is the sum of the digits in a single repeating period? (In other words, what is the sum of the digits covered by the repeat bar?)
Let t = 0.1212121212........
then 100t= 12.12121212.....
100t - t = 12
99t=12
t= 12/99
0.1212121212... = 12/99
Now do the same thing with 0.345345345.....
only since there are 3 digits repeating you will have to multiply by 1000.
Now if you understand what i have written you can finish it yourself.