Restrictions for the expression 1/(2-secx)

Question

0

797

1

+154

Restrictions for the expression 1/(2-secx)?

sportslover Jun 5, 2014

+129852

+5

Best Answer

Where 2-secx = 0

So secx = 2 or cosx = (1/2)

So we have (pi/3 + 2n*pi) and (5/3)pi + 2n*pi).....where n is an integer

CPhill Jun 5, 2014

CPhill · Answer 1 · 2014-06-05T06:35:18

Where 2-secx = 0

So secx = 2 or cosx = (1/2)

So we have (pi/3 + 2n*pi) and (5/3)pi + 2n*pi).....where n is an integer