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avatar+12 

How can the function

 

 \(f(x) = 5+{1 \over x+3}\)

 

be written as 

 

\(f(x) = {ax+b \over x+3}\)

 

Thanks in advance!

 Mar 14, 2016

Best Answer 

 #2
avatar+1904 
+10

\(f(x)=5+\frac{1}{x+3}\)

 

\(f(x)=\frac{5}{1}+\frac{1}{x+3}\)

 

\(f(x)=\frac{5\times(x+3)}{1\times(x+3)}+\frac{1}{x+3}\)

 

\(f(x)=\frac{5x+15}{x+3}+\frac{1}{x+3}\)

 

\(f(x)=\frac{5x+15+1}{x+3}\)

 

\(f(x)=\frac{5x+16}{x+3}\)

.
 Mar 14, 2016
edited by gibsonj338  Mar 14, 2016
 #1
avatar+2499 
+5

 \(f(x) = 5+{1 \over x+3} \\ f(x) = {5(x+3)\over x+3}+{1 \over x+3} \\ f(x) =\frac{5x+16}{x+3} \text{ same as } \frac{ax+b}{x+3}\\ a=5 \\ b=16\)

.
 Mar 14, 2016
edited by Solveit  Mar 14, 2016
 #2
avatar+1904 
+10
Best Answer

\(f(x)=5+\frac{1}{x+3}\)

 

\(f(x)=\frac{5}{1}+\frac{1}{x+3}\)

 

\(f(x)=\frac{5\times(x+3)}{1\times(x+3)}+\frac{1}{x+3}\)

 

\(f(x)=\frac{5x+15}{x+3}+\frac{1}{x+3}\)

 

\(f(x)=\frac{5x+15+1}{x+3}\)

 

\(f(x)=\frac{5x+16}{x+3}\)

gibsonj338 Mar 14, 2016
edited by gibsonj338  Mar 14, 2016

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