How can the function
\(f(x) = 5+{1 \over x+3}\)
be written as
\(f(x) = {ax+b \over x+3}\)
Thanks in advance!
\(f(x)=5+\frac{1}{x+3}\)
\(f(x)=\frac{5}{1}+\frac{1}{x+3}\)
\(f(x)=\frac{5\times(x+3)}{1\times(x+3)}+\frac{1}{x+3}\)
\(f(x)=\frac{5x+15}{x+3}+\frac{1}{x+3}\)
\(f(x)=\frac{5x+15+1}{x+3}\)
\(f(x)=\frac{5x+16}{x+3}\)
.\(f(x)=5+\frac{1}{x+3}\)
\(f(x)=\frac{5}{1}+\frac{1}{x+3}\)
\(f(x)=\frac{5\times(x+3)}{1\times(x+3)}+\frac{1}{x+3}\)
\(f(x)=\frac{5x+15}{x+3}+\frac{1}{x+3}\)
\(f(x)=\frac{5x+15+1}{x+3}\)
\(f(x)=\frac{5x+16}{x+3}\)