+0  
 
-5
294
1
avatar+956 

 Rewrite in simplest radical form:

 Apr 6, 2019
 #1
avatar+111392 
0

 √[8a^3b^5 ]  =    √[ 4 * 2 * a^2 * a *  b^4 * b ]  =

 

(4)^(1/2) * (2)^(1/2) * (a^2)^(1/2) * (a)^(1/2) * (b^4)^(1/2) * (b)^(1/2) =

 

2 * (2)^(1/2) * a * (a)^(1/2) * b^2 * b^(1/2) =

 

2ab^2   √ [ 2ab]

 

 

 √[50x^3y^2 ] =   √ [ 25 * 2 * x^2 * x * y^2 ]  =

 

(25)^(1/2) * (2)^(1/2) * (x^2)^(1/2) * (x)^(1/2) * (y^2)^(1/2) =

 

5 * (2)^(1/2) * x * (x)^(1/2) * y  =

 

5 xy  √[ 2x]

 

 

cool cool cool

 Apr 6, 2019

14 Online Users

avatar
avatar